0.5t^2-t+0.25=0

Solution for 0.5t^2-t+0.25=0 equation:

0.5t^2-t+0.25=0

We add all the numbers together, and all the variables

0.5t^2-1t+0.25=0

a = 0.5; b = -1; c = +0.25;
Δ = b2-4ac
Δ = -12-4·0.5·0.25
Δ = 0.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.5}}{2*0.5}=\frac{1-\sqrt{0.5}}{1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.5}}{2*0.5}=\frac{1+\sqrt{0.5}}{1}
$